Question

Derivata de ordinul 1:
f:R->R, f(x)= 2^x -xlnx

Answer 1

f'(x)=(2^x-xlnx)' = (2^x)'-(xlnx)'

(xlnx)'=x'lnx+x(lnx)'=lnx+x*1/x=lnx+1

(2^x)'=2^x*ln2

Deci f'(x) = 2^x*ln2-(lnx+1)