Question

descompune in factori:
am nevoie de punctul g) (2x + 1)³ - 18x - 9=
și punctul h) de la exercițiul 5 și tot exercițiul 6 rezolvat daca se poate !!! URGENT dau coroană VA ROG ​

Answer 1

Răspuns:

Explicație pas cu pas:

6) a) 9(x-2)²-4(3x-7)² = [3(x-2)]²-[2(3x-7)]² = (3x-6)²-(6x-14)²=

= (3x-6-6x+14)(3x-6+6x-14) = (8-3x)(9x-20)

b) 4(5x+3)²-25(x-2)² = [2(5x+3)]²-[5(x-2)]² = (10x+6)²-(5x-10)²=

= (10x+6-5x+10)(10x+6+5x-10) = (5x+16)(15x-4)

c) 4x²+8x+4 - (x+3)² = (2x+2)²-(x+3)² = (2x+2-x-3)(2x+2+x+3) =

= (x-1)(3x+5)

d) (3x+2)²-9x²-18x-9 = (3x+2)²-(3x+3)² = (3x+2-3x-3)(3x+2+3x+3) =

= (-1)(6x+5) = -6x-5

e) (2x+3)³-2x-3 = (2x+3)³-(2x+3) = (2x+3)[(2x+3)²-1]=

= (2x+3)(2x+3-1)(2x+3+1) = (2x+3)(2x+2)(2x+4) = 4(2x+3)(x+1)(x+2)

f) (3x-5)³ - 12x+20 = (3x-5)³ -4(3x-5) = (3x-5)[(3x-5)²-4] =

= (3x-5)(3x-5-2)(3x-5+2) = (3x-5)(3x-7)(3x-3)

g) (2x+1)³-18x-9 = (2x+1)³-9(2x+1) = (2x+1)[(2x+1)²-9] =

= (2x+1)(2x+1-3)(2x+1+3) = (2x+1)(2x-2)(2x+4) = 4(2x+1)(x-1)(x+2)

h) (3x+1)³-3x-1 = (3x+1)³-(3x+1) = (3x+1)[(3x+1)²-1] =

= (3x+1)(3x+1-1)(3x+1+1) = (3x+1)(3x)(3x+2) = 3x(3x+1)(3x+2)

pentru 5)g) si 5)h) raspunsul este aici :

https://brainly.ro/tema/10359560