Question

descompune in factori, folosind factorul comun​

Answer 1

Răspuns:

a)

12x^4 + 8x^3 - 16x^2 = 4x^2 × (3x^2 + 2x - 4)  

b)

20y^5 - 16x^6 + 12y^3 ​- 8y^4 = 4y^3 × (5y^2 - 4y^3 + 3 - 2y)

C)

15a^5 - 9a^4 + 6a^6 =  3a^4 × (5a - 3 + 2a^2)

D)

12y^4 + 18y^3 - 30y^5 + 12y^2 = 6y^2 × (2y^2 + 3y - 5y^3 + 2)  

E)

4a^3 - 8a^4 + 4a^2 = 4a^2 × (a - 2a^2 + 1)  

F)

15x^2 + 20x^4 - 25x^3 = 5x^2 × (3 + 4x^2 - 5x)

Explicație pas cu pas: