Question

descompune în factori x patrat-8x-20​

Answer 1

x^2 - 8x - 20

delta=(-8)^2 - 4•(-20)=64+80=144

rad.delta=12

x1=(8-12)/2=(-2)

x2=(8+12)/2=10

x^2 - 8x - 20 = (x+2)(x-10)

Answer 2

x² - 8x - 20 =

= x² - 10x + 2x - 20

= x(x - 10) + 2(x - 10)

= (x + 2)(x - 10)