Question

Descompune in factori: x²+2x-63.
Va rog euuu

Answer 1

x²-7x+9x-63=x(x-7)+9(x-7)=(x+9)(x-7)

Answer 2

  
[tex]\displaystyle\\ \text{Calculam radacinile ecuatiei:}\\ x^2+2x-63=0\\\\ x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}= \frac{-2\pm \sqrt{4+4\cdot 63}}{2}= \\\\ =\frac{-2\pm \sqrt{4(1+ 63)}}{2}=\frac{-2\pm \sqrt{4\cdot 64}}{2}=\frac{-2\pm 2\cdot 8}{2}=-1\pm 8\\ x_1 = -1+8=\boxed{7}\\ x_2 = -1-8=\boxed{-9}\\\\ \Longrightarrow~~~x^2+2x-63 = \boxed{\bf (x+9)(x-7)} [/tex]