Question

Descompune numarul 2145 in factori primi si scrie multimea divizorilor sai.

Answer 1

2145=3*5*11*13
Nr. divizorilor lui 2145: (1+1)*(1+1)*(1+1)*(1+1)=2*2*2*2=16
D2145∈{1,3,5,11,13,15,33,39,55,65,143,165,195,429,715,2145}