Question

descompunerea in factori primi a expresiei a=(x-3)^2 -16 va rog ajutati-ma urgentt

Answer 1

$(x-3)^2-16=x^2+3^2-2*3*x-16=x^2+9-6x-16=x^2-6x-7=(x+1)(x-7)$

Answer 2

   
[tex]\texttt{Folosim formula: } \bold{a^2-b^2 = (a+b)(a-b) }\\ \\ \bold{a=(x-3)^2 -16 = (x-3)^2 -4^2 =} \\ \\ \bold{= (x-3+4)(x-3-4)=} \boxed{\bold{(x+1)(x-7)}}[/tex]