Question

descompunerii în factori

Answer 1

   
[tex]\displaystyle \bf\\ 2x^3-12x^2+18x =\\ =2x(x^2-6x+9)=\\ =2x(x^2+2\cdot x\cdot (-3)+(-3)^2)=\\ =\boxed{\bf 2x(x-3)^2}=\boxed{\bf 2x(x-3)(x-3)}\\\\\\ 5x^4+30x^3+45x^2=\\ =5x^2(x^2+6x+9)=\\ =5x^2(x^2+2\cdot x\cdot 3+3^2)=\\ =\boxed{\bf 5x^2(x+3)^2}=\boxed{\bf 5x^2(x+3)(x+3)}\\\\\\ 3x^4-24x^3+48x^2=\\ =3x^2(x^2-8x+16)=\\ =3x^2(x^2+2\cdot x\cdot(-4)+(-4)^2)=\\ =\boxed{\bf 3x^2(x-4)^2}=\boxed{\bf 3x^2(x-4)(x-4)}[/tex]