Question

descompunerii in factori :
${x }^{2} + 6x + 8$
repede va rog!!!!!!!!!

Answer 1

Salut,

x² + 6x + 8 = x² + 6x + 9 -- 1 = x² + 2·x·3 + 3² -- 1² = (x + 3)² -- 1² =

= (x + 3 -- 1)(x + 3 + 1) = (x + 2)(x + 4).

Am folosit formulele de calcul prescurtat:

a² + 2·a·b + b² = (a + b)²

m² -- n² = (m -- n)(m + n).

A fost greu ?

Green eyes.

Answer 2

x² + 6x + 8 =

x² + 2x + 4x + 8 =

x(x + 2) + 4(x+ 2) =

(x + 2) ( x + 4)