Question

Descompunerii in factori:x^2+2x-8;x^2-2x-3;x^2+2x-3;x^2-x-6;x^2-3x-4;x^2+7x-18;x^2-5x-6;x^2-3x-10;x^2-6x-7;x^2-5'-14;x^2-11x-26;x^2-11x-12;x^2-8x-20;x^2+3x-4;x^2+5x-6;x^2-13x-14;x^2+4x-5;x^2+5x-24;x^2-6x-7.

Answer 1

x^2+2x-8;=(x-2)(x+4)
x^2-2x-3;=(x+1)(x-3)
x^2+2x-3;=(x-1)(x+3)
x^2x-6;=x^3-6
x^2-3x-4;=(x+1)(x-4)
x^2+7x-18;=(x-2)(x+9)
x^2-5x-6;=(x+1)(x-6)
x^2-3x-10;=(x+2)(x-5)
x^2-6x-7;=(x+1)(x-7)
x^2-5'-14;=x^2-19
x^2-11x-26;=(x+2)(x-13)
x^2-11x-12;=(x+1)(x-12)
x^2-8x-20;=(x+2)(x-10)
x^2+3x-4;=(x-1)(x+4)
x^2+5x-6;=(x-1)(x+6)
x^2-13x-14;=(x+1)(x-14)
x^2+4x-5;=(x-1)(x+5)
x^2+5x-24;=(x-3)(x+8)
x^2-6x-7.=(x+1)(x-7)