Question

Descompunerii in factori:x^2+3x+2;x^2+7x+10;x^2+11x+30;x^22+9x+8;x^2+5x+4;x^2+9x+20;x^2-13x+42;x^2+15x+56;x^2+13x+42;x^2+7x+12;x^2+8x+15;x^2+12x+35;x^2+11x+18;x^2-12x+20;x^2-7x+12;x^2-9x+14;x^2-5x+4;x^2-9x+20;x^2-14x+48;x^2-8x+7

Answer 1

x^2+3x+2=x^2+2x+x+2=x(x+2)+(x+2)=(x+2)(x+1)
x^2+7x+10=x^2+5x+2x+10=(x+5)(x+2)
x^2+11x+30=x^2+6x+5x+30=(x+6)(x+5)
x^2+9x+8=x^2+8x+x+8=(x+8)(x+1)
x^2+5x+4=x^2+4x+x+4=(x+4)(x+1)
x^2+9x+20=x^2+5x+4x+20=(x+5)(x+4)
x^2-13x+42=x^2-6x-7x+42=(x-6)(x-7)
x^2+15x+56=x^2+7x+8x+56=(x+7)(x+8)
x^2+13x+42=x^2+6x+7x+42=(x+6)(x+7)
x^2+7x+12=x^2+4x+3x+12=(x+4)(x+3)
x^2+8x+15=x^2+5x+3x+15=(x+5)(x+3)
x^2+12x+35=x^2+7x+5x+35=(x+7)(x+5)
x^2+11x+18=x^2+9x+2x+18=(x+9)(x+2)
x^2-12x+20=x^2-10x-2x+20=(x-10)(x-2)
x^2-7x+12=x^2-4x-3x+12=(x-4)(x-3)
x^2-9x+14=x^2-7x-2x+14=(x-7)(x-2)
x^2-5x+4=x^2-4x-x+4=(x-4)(x-1)
x^2-9x+20=x^2-5x-4x+20=(x-5)(x-4)
x^2-14x+48=x^2-6x-8x+48=(x-6)(x-8)
x^2-8x+7=x^2-7x-x+7=(x-1)(x-7)