Question

descompuneti
1)2x²-12x+16
2)2x³+8x²+8x​

Answer 1

Răspuns: Ai mai jos descompunerile

Explicație pas cu pas:

Buna!

1)

2x² - 12x + 16

2 · (x² - 6x + 8) =

2 · (x² - 2x - 4x + 8) =

2 · [x · (x - 2) - 4 · (x - 2)] =

2 · (x - 2) · (x - 4)

2)

2x³ + 8x² + 8x​ =

2x · (x² + 4x + 4) =

2x · (x + 2)²

==pav38==

Answer 2

1)

$\it 2x^2-12x+16=2(x^2-6x+8)=2(x^2-6x+9-1)=2[(x-3)^2-1] =\\ \\ =2(x-3-1)(x-3+1)=2(x-4)(x-2)$

2)

$\it 2x^3+8x^2+8x=2x(x^2+4x+4)=2x(x+2)^2$