Question

descompuneti: 2x^2+8x+3​

Answer 1

Explicație pas cu pas:

2x²+8x+3=0

a=2 b=8 c=3

/\=b²-4ac=>/\=64-4*2*3=>/\=64-24=>/\=40

x1=(-b+V/\)/2a=(-8+V40)/4=(-8+2V10)/4=2(V10-4)/4

=(V10-4)/2

x2=(-b-V/\)/2a=(-8-2V10)/4=2(-4-V10)/4=-(4+V10)/2

2x²+8x+3=a(x-x1)(x-x2)=2[x-(V10-4)/2]*[x+(4+V10)/2] =

(2x-V10+4)*[x+(4+V10)/2]

*/\=delta