Question

descompuneti factori folosind metoda gruparii​

Answer 1

Explicație pas cu pas:

a)

$2a + b + 2 {a}^{2} + ab = \\ = (2a + b) + a(2a + b)\\ = (2a + b)(a + 1)$

b)

$3a + 3 {a}^{2} - b - ab = \\ = 3a(1 + a) - b(1 + a)\\ = (a + 1)(3a + b)$

c)

$2 {x}^{2} - 3x + 4ax - 6a = \\ = x(2x - 3) + 4a(2x - 3)\\ = (2x - 3)(x + 4a)$

d)

${x}^{2}{y}^{2} + xy + axy + a = \\ = xy(xy + 1) + a(xy + 1)\\ = (xy + 1)(xy + a)$

e)

$ab + ac + am + by + yc + ym = \\ = a(b + c + m) + y(b + c + m)\\ = (b + c + m)(a + y)$

f)

$xy - {x}^{2} {y}^{2} + {x}^{3} {y}^{3} - a + axy - a{x}^{2} {y}^{2} = \\ = xy(1 - xy + {x}^{2} {y}^{2}) - a(1 - xy + {x}^{2} {y}^{2}) \\ = (1 - xy + {x}^{2} {y}^{2})(xy - a)$