Question

descompuneti in baza 2 Nr:8,13,14,19,20,59,128,135,512,1024,2023​

Answer 1

8₍₁₀₎ = 2³ = 1·2³+0·2²+0·2¹+0·2⁰ = 1000₍₂₎

13₍₁₀₎ = 8+4+1 = 1·2³+1·2²+0·2¹+1·2⁰ = 1101₍₂₎

14₍₁₀₎ = 8+4+2 = 1·2³+1·2²+1·2¹+0·2⁰ = 1110₍₂₎

19₍₁₀₎ = 16+2+1 = 1·2⁴+0·2³+0·2²+1·2¹+0·2⁰ = 10010₍₂₎

20₍₁₀₎ = 16+4 = 1·2⁴+0·2³+1·2²+0·2¹+0·2⁰= 10100₍₂₎

59₍₁₀₎ = 32+16+8+2+1 = 1·2⁵+1·2⁴+1·2³+0·2²+1·2¹+1·2⁰ = 111011₍₂₎

128₍₁₀₎ = 2⁷ = 10000000₍₂₎

135₍₁₀₎ = 128+4+2+1 = 10000111₍₂₎

512₍₁₀₎ = 2⁹ = 1000000000₍₂₎

1024₍₁₀₎ = 2¹⁰ = 10000000000₍₂₎

2023​₍₁₀₎ = 1024+512+256+128+64+32+4+2+1 = 11111100111₍₂₎