Question

Descompuneți în factori. 16a²-x²+2x-1​

Answer 1

 

$\displaystyle\bf\\Descompunem~in~factori:~~~~~ 16a^2-x^2+2x-1\\\\Folosim~formulele:\\\\a^2-2ab+b^2=(a-b)^2\\\\a^2-b^2=(a+b)(a-b)\\\\Rezolvare:\\\\16a^2-x^2+2x-1=\\\\=(16a^2)-(x^2-2x+1)=\\\\=(16a^2)-(x^2-2\times x\times1+1^2)=\\\\=(4a)^2-(x-1)^2=\\\\=(4a+(x+1))(4a-(x+1))=\\\\=\boxed{\bf(4a+x+1)(4a-x-1)}$

 

 

Answer 2

$16a^2-x^2+2x-1=4^2a^2-(x^2-2x+1)=(4a)^2-(x-1)^2=(4a-x+1)(4a+x-1)$