Question

Descompuneti in factori
(3x+5)la puterea a doua -(x+1)la puterea a doua

(x+√2)la puterea a doua -8


(2x+√3)la puterea a doua - 27

Answer 1

$(3x+5)^{2} - (x+1)^{2} =9 x^{2} +30x+25- x^{2} -2x-1=8 x^{2} +28x+24$
$(x+ \sqrt{2} )^{-8} = \frac{1}{(x+ \sqrt{2} )^{8}} = \frac{1}{[(x+ \sqrt{2} )^{2}]^4}} = \frac{1}{ (x^{2} +2 \sqrt{2}x+2)4 }$
$(2x+ \sqrt{3} )^{2} -27=4 x^{2} +4 \sqrt{3} x+3-27=4 x^{2}+4 \sqrt{3} x-24= \\ =4( x^{2} + \sqrt{3} x-6)$