Question

Descompuneti in factori:
a) (2x+3)^2-(x+1)^2
b)(3x-7)^2-(x+2)^2
c)(4x+1)^2-(3x-2)^2
d)(2x+3y)^2-(x-2y)^2

Answer 1

$(2x+3)^{2}-(x+1) ^{2} =(2x+3-x-1)(2x+3+x+1)= \\ =(x+2)(3x+4) \\ (3x-7) ^{2}-(x+2) ^{2}=(3x-7-x-2)(3x-7+x+2)= \\ =(2x-9)(4x-5) \\ (4x+1) ^{2} -(3x-2) ^{2}=(4x+1-3x+2)(4x+1+3x-2)= \\ =(x+3)(7x-1) \\ (2x+3y) ^{2} -(x-2y)^{2}=(2x+3y-x+2y)(2x+3y+x-2y)= \\ =(x+5y)(3x+y)$
Am folosit peste tot diferenta de patrate.Succes la tema! :)

Answer 2

a)4x^2+6x+9-x^2+2x+1=3x^2+8x+10
b)9x^2-42x+49-x^2+4x-4=8x^2-38x+45
c)16x^2+8x+1-9x^2-12x+4=7x^2-4x-4
d)4x^2+6xy+9y^2-x^2-4xy-4y^2=3x^2+2xy-5y^2
cred ca e corect