Question

Descompuneți in factori :
a) 3x^3 - 3x ^2 - 6x

Answer 1

3x^3 - 3x ^2 - 6x =x(3x^2-3x-6)=x(3x-2)(x+1); ;3x^2-3x-6=0 ; delta =9+72=81; x1=-1;x2=3/2; 3x^2-3x-6=(3x-2)(x+1)

Answer 2

$3x^{3} + x^{2} +6x=$

$3x( x^{2}+x+2)$