Question

Descompuneti in factori:a) 4(x+2)+y(x+2)
b) (x-2)·x+4(x-2)
c) -3a(x+3)+6b(x=3)

Answer 1

a)(x+2)(4+y)
b)(x-2)(x+4)
c)(x+3)(-3a+6b)=-3(x+3)(a-2b)

Answer 2

a)4(x+2)+y(x+2)=(x+2)(4+y)
b)(x-2)·x+4(x-2)=(x-2)(x+4)
c)-3a(x+3)+6b(x+3)=(x+3)(6b-3a)=3·(x+3)(2b-a)