Matematică, întrebare adresată de cooky15, 9 ani în urmă

Descompuneți in factori:
a)4x la patrat-9
16x la patrat -25
X la patrat-49
4x la patrat -25
X la patrat-62
b)X la patrat-100
36-25x la patrat
49-4x la patrat
64-25x la patrat
81-49x la patrat
c)X la patrat-121
169x la patrat-49
81x la patrat-49y la patrat
25x la patrat-y la patrat
36x la patrat-25y la patrat
d)5x la patrat-1
3x la patrat-5
7x la patrat-2
9x la patrat-5
4x la patrat-3
2x la patrat-1

Răspunsuri la întrebare

Răspuns de iakabcristina2
1
a)(2x-3)(2x+3)
(4x-5)(4x+5)
(x-7)(x+7)
(2x-5)(2x+5)
(x-rad62)(x+rad62)
b)(x-10)(x+10)
(6-5x)(6+5x)
(7-2x)(7+2x)
(8-5x)(8+5x)
(9-7x)(9+7x)
c)(x-11)(x+11)
(13x-7)(13x+7)
(9x-7y)(9x+7y)
(5x-y)(5x+y)
(6x-5y)(6x+5y)
d)(xrad5-1)(xrad5+1)
(xrad3-rad5)(xrad3+rad5)
(xrad7-rad2)(xrad7+rad2)
(3x-rad5)(3x+rad5)
(2x-rad3)(2x+rad3)
(xrad2-1)(xrad2+1)
Răspuns de icecon2005
1
a² – = (a – b)(a + b)
a)4x la patrat-9=(2x-3)(2x+3)
16x la patrat -25=(4x-5)(4x+5)
X la patrat-49=(x-7)(x+7)
4x la patrat -25=4x²-25=(2x-5)(2x+5)
X la patrat-64=(x-8)(x+8)
b)X la patrat-100=(x-10)(x+10)
36-25x la patrat=(6-5x)(6+5x)
49-4x la patrat=(7-2x)(7+2x)
64-25x la patrat=(8-5x)(8+5x)
81-49x la patrat=(9-7x)(9+7x)
c)X la patrat-121=(x-11)(x+11)
169x la patrat-49=(13x-7)(13+7)
81x la patrat-49y la patrat=(9x-7y)(9x+7y)
25x la patrat-y la patrat=25²-y²=(5x-y)(5x+y)
36x la patrat-25y la patrat=36x²-25y²=(6x-5y)(6x+5y)
d)5x la patrat-1=(x√5-1)(x√5+1)
3x la patrat-5=
(x√3-√5)(x√3+√5)
 7x la patrat-2=
(x√7-√2)(x√7+√2)
 9x la patrat-5=(3x-√5)(3x+√5)
 4x la patrat-3=(2x-√3)(2x+√3)
2x la patrat-1 =(x√2-1)(x√2+1)

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