Question

Descompuneti în factori:
a) 5x(x+2)+10(x+2)
b) (x+y)²-z²
c) x³-4x²+4x
d) x³+x²t+xt²+t³
URGEEENT!! DAU COROANA!! MERSI!
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Answer 1

Răspuns:

Explicație pas cu pas:

a) 5x(x+2)+10(x+2) =5(x+2)(x+2)=5(x+2)²

b) (x+y)²-z²=(x+y+z)(x+y-z)

c) x³-4x²+4x=x(x²-4x+4)=x[(x²-4) -(4x-4-4)]=x[(x-2)(x+2)-(4x-8)]=x[(x-2)(x+2)-4(x-2)]=x[(x-2)(x+2-4)]=x(x-2)(x-2)=x(x-2)²

d) (x³+t³)+(x²t+xt²) = (x+t)(x²-xt+t²)+xt(x+t)=(x+t)(x²-xt+t²+xt)=(x+t)(x²+t²)