Question

Descompuneti in factori;
a)64x³-(x-1)³;
b)[tex] \frac{1}{8} t^{3}+(1+ \frac{1}{2}t) ^{3};
[/tex]
c)1-(z+1)⁶.

Answer 1

se bazeaza pe formula 
(a³-b³)=(a-b)(a²+ab+b²)
a) (4x-x+1)[16x²+4x(x-1)+(x-1)²]=(3x+1)(16x²+4x²-4x+x²-2x+1)=(3x+1)(21x²-6x+1)

b) (1/2t+1+1/2t)[1/4 .t²-1/2t(1+1/2t)+(1+1/2t)²]=(t+1)(1/4t²-1/2t-1/4t²+1+t+1/4t²)=
(t+1)(1/4t²+1/2t+1)

c) [1-(z+1)²][1+(z+1)²+(z+1`)^4]=
(1-z²-z-1)[1+(z+1)²+(z+1)^4]=
(-z²-z)(1+(z+1)²+(z+1)^4]