Question

descompuneti in factori:
a)7ab²+14a²b=
b)-3,6x²y³+0,8x la puterea a 4y la puterea a 5
c)2√17y la puterea a 4-√17x²y
d)-15tz²-√5t²z
e)x(3-y)+5(y-3)
f)2,5a(a-1)-(1-a)

Answer 1

a)7ab²+14a²b=7ab(b+2a)

b)-3,6x²y³+0,8x⁴y⁵=
=-0,8x²y³(4,5-x²y²)

c)2√17y⁴-√17x²y=
=√17y(2y³-x²)

d)-15tz²-√5t²z=
=-tz(15z-√5t)

e)x(3-y)+5(y-3)=
=x(3-y)-5(3-y)=
=(3-y)(x-5)

f)2,5a(a-1)-(1-a)=
=2,5a(a-1)+(a-1)=
=(a-1)(2,5a+1)