Question

descompuneti in factori:
a)$\sqrt{3 y^{2} }$ + 2$\sqrt{15}y$ + 5$\sqrt{3}$
b)${7} ay^{2} -28ay+28a$

Answer 1

a) =rad3[rad(y^2)+2rad(5y)+5]=rad3(rady+rad5)^2

b)=7a(y^2-4a+4)=7a(y-2)^2

unde ^ inseamna putere