Question

Descompuneți în factori:
a) (x + 1)(x + 3)2 - 4(x + 1);
b) (x+3)(2x + 1)2 - 16(x + 3);
c)(x - 3)(x + 2)2 -x +3;
d) (x - 4)(2x + 1)2 - x +4;
Repede va rog multtt! Dau 50 de puncte!​

Answer 1

a) (x+1)(x+3)²-4(x+1) = (x+1)((x+3)²-4) = (x+1)(x+3-2)(x+3+2) = (x+1)(x+1)(x+5) = (x+1)²(x+5)

b) (x+3)(2x+1)²-16(x+3) = (x+3)((2x+1)²-16) = (x+3)(2x+1-4)(2x+1+4) = (x+3)(2x-3)(2x+5)

c) = (x-3)(x+2)²-(x-3) = (x-3)((x+2)²-1) = (x-3)(x+2-1)(x+2+1) = (x-3)(x+1)(x+3)

d) = (x-4)(2x+1)²-(x-4) = (x-4)((2x+1)²-1) = (x-4)(2x+1-1)(2x+1+1) = 2x(x-4)(2x+2) = 4x(x-4)(x+1)

Answer 2

Răspuns:

Ai rezolvarea in imagini!