Question

Descompuneți în factori : a)x^2 + 2x - 3. b)x^2 + x - 2. c)x^2 + x - 6 d)x^2 + 2x - 8. e)x^2 - x - 6. f)x^2 - x - 2. g) x^2 + 4x - 12. h)x^2 - 2x - 3

Dau coroană

Answer 1

Raspuns:

Explicație pas cu pas:

a)x^2+2x-3=x^2-x+3x-3=x(x-1)+3(x-1)=(x-1)(x+3)

b)x^2+x-2=x^2-x+2x-2=x(x-1)+2(x-1)=(x-1)(x+2)

c)x^2+x-6=x^2+3x-2x-6=x(x+3)-2(x+3)=(x+3)(x-2)

d)x^2+2x-8=x^2+2x-8+9=(x+1)^2-9=(x+1+3)(x+1-3)=(x+4)(x-2)

e)x^2-x-6=x^2+2x-3x-6=x(x+2)-3(x-2)=(x-2)(x-3)

f)x^2-x-2=x^2+2x+x-2=x(x-2)+(x-2)=(x-2)(x-1)

g)x^2+4x-12=x^2-6x+2x-12=x(x-6)+2(x-6)=(x-6)(x+2)

h)x^2-2x-3=x^2-3+x-3=x(x-3)+(x-3)=(x-3)(x+1)