Question

descompuneti in factori
a)x²-7x+12
b)x²-10x+21
c)x²-x-56
d)x²-8x+15
e)x²-2x-15
f)x²-4x-45
ajutooor, trebuie urgent dau coroana

Answer 1

Explicație pas cu pas:

x²-7x+12=x²-3x-4x+12=x(x-3)-4(x-3)=(x-3)(x-4)

x²-10x+21=x²-3x-7x+21=x(x-3)-7(x-3)=(x-3)(x-7)

x²-x-56=x²+7x-8x-56=x(x+7)-8(x+7)=(x+7)(x-8)

x²-8x+15=x²-3x-5x+15=x(x-3)-5(x-3)=(x-3)(x-5)

x²-2x-15=x²+3x-5x-15=x(x+3)-5(x+3)=(x+3)(x-5)

x²-4x-45=x²+5x-9x-45=x(x+5)-9(x+5)=(x+5)(x-9)

Answer 2

a.)(x-4)(x-3)

b.)(x-7)(x-3)

c.)(x-8)(x+7)

d.)(x-3)(x-5)

e.)(x-3)(x+5)

f.)(x-5)(x+9)