Question

Descompuneti in factori:

a)xla a doua-3x+2
b)xla a doua-6x+8
c)xla a doua-4x+3

Answer 1

a)
x^2-3x+2=
=x^2-x-2x+2=
=x×(x-1)-2 (x-1)=
=(x-1)×(x-2)

b)
x^2-6x+8=
=x^2-2x-4x+8=
=x×(x-2)-4 (x-2)=
=(x-2)×(x-4)

c)
x^2-4x+3=
=x^2-2x-2x+3=
=x×(x-1)-3 (x-1)=
=(x-1)×(x-3)

Answer 2

a) x^2 - 3x + 2 = x^2 - x - 2x + 2 = x(x-1) - 2(x-1) = (x-1)(x-2)

b) x^2 - 6x + 8 = x^2 - 2x - 4x + 8 = x(x-2) - 4(x-2) = (x-2)(x-4)

c) x^2 - 4x + 3 = x^2 - x - 3x + 3 = x(x-1) - 3(x-1) = (x-1)(x-3)