Question

Descompuneti in factori , aplicand foemula a^2-b^2 = ( a+b) (a-b )
1. 4(x-1)^2-1
2.25(2x-y)^2 -36(x+2y)^2
3.16(3a-b)^2 -9(a+b)^2
Repede ,dau coroana !!!

Answer 1

1. = [4(x-1)-1][4(x-1)+1]=(4x-4-1)(4x-4+1)=(4x-5)(4x-3)
2. = [5(2x-y) -6(x+2y)][5(2x-y) +6(x+2y)]=(10x-5y-6x-12y)(10x-5y+6x+12y= (4x-17y)(16x+5y)
3. = [4(3a-b)-3(a+b)][4(3a-b)+3(a+b)]= (12a-4b-3a-3b)(12a-4b+3a+3b) = (9a-7b)(15a-b)