Question

Descompuneti in factori ,aplicand formula a^2-b^2=(a+b)(a-b):
a)(x-2)^2-3^2=
b)(x+1)^2-4^2=
d)(x-1)^2-4^2=
e)(3a+b)^2-a^2=
f)(7m+n)^2-4n^2=
g)(x+y+1)^2-x^2=
h)(3x+4y)^2-49a^2=

Answer 1

a)(x-2)^2-3^2=(x-2-3)(x-2+3)=(x-5)(x+1)
b)(x+1)^2-4^2=(x+1-4)(x+1+4)=(x-3)(x+5)
d)(x-1)^2-4^2=(x-1-4)(x-1+4)=(x-5)(x+3)
e)(3a+b)^2-a^2=(3a+b-a)(3a+b+a)=(2a+b)(4a+b)
f)(7m+n)^2-4n^2=(7m+n-2n)(7m+n+2n)=(7m-n)(7m+3n)
g)(x+y+1)^2-x^2=(x+y+1-x)(x+y+1+x)=(y+1)(2x+y+1)
h)(3x+4y)^2-49a^2=(3x+4y-7a)(3x+4y+7a)