Question

Descompuneti in factori diferenta de patrate:
(2x-1)^2 - 16 =.............=............
9-(5x-6)^2 =................=.............=.............
(4a-b)^2 -(2a+3b)^2 =..................=...............=........=.......

Answer 1

Răspuns:

(2x-1)^2-4^2=(2x-1-4)(2x-1+4)=(2x-5)(2x+3)

3^2-(5x-6)^2=[3-(5x-6)][3+(5x-6)]=(-5x+9)(5x-3)

(4a-b)^2-(2a+3b)^2=(4a-b-2a-3b)(4a-b+2a+3b)=(2a-4b)(6a+2b)=2x2(a-2b)(3a+b)=4(a-2b)(3a+b)

Answer 2

Răspuns:

Explicație pas cu pas: