Question

Descompuneti in factori : E(x)=3x(x-3)-(x-3)(2x-1)
F(a)=(a+1) la a 2 a -3a(a+1)
G(x)=(x+2)(x+1)-(x+2)(2x-1)
H(x)=(x+1) la a 2 a -x(x+1)

Answer 1

Răspuns:

Explicație pas cu pas:

E(x)=3(x-3)-(x-3)(2x-1) dam factor comun pe (x-3)

==>E(x)=(x-3)*[3-(2x-1)

E(x)=(x-3)*(-6x+3)

E(x)=-6x^2-9+18x+3x=6x^2+21x-9(faci cu delta)

F(a)=(a+1)^2-3a(a+1)

Dam factor comun pe (a+1)

F(a)=(a+1)(a+1-3a)=(a+1)(-2a+1)=-2a^2+a-2a+1=-2a^2-a+1

G(x)=(x+2)(x+1)-(x+2)(2x-1)=(x+2)[(x+1)-(2x-1)=(x+2)*(-x)

H(x)=(x+1)^2-x(x+1)=(x+1)[(x+1)-x]=(x+1)