Question

Descompuneti în factori expresia : x^3-4x^2+x+6

Answer 1

$\it x^3-4x^2+x+6=x^3-2x^2-2x^2+4x-3x+6=\\ \\ =x^2(x-2)-2x(x-2)-3(x-2)=(x-2)(x^2-2x-3)=\\ \\ =(x-2)(x^2-3x+x-3)=(x-2)[x(x-3)+(x-3)]=\\ \\ =(x-2)(x-3)(x+1)=(x+1)(x-2)(x-3)$