Question

Descompuneți în factori folosind metoda factorului comun​

Answer 1

a) (x+1)(2x-3) + (x+1)² = (x+1)(2x-3 + x + 1) = (x+1)(3x-2)

b) (x-2)² + (3-5x)(x-2) = (x-2)(x-2 + 3-5x) = (x-2)(-4x+1)

c) (x+3)(5x-4) - (x+3)² = (x+3)(5x-4 - x-3) = (x+3)(4x-7)

d) (6x+1)(x+4) - (x+4)² = (x+4)(6x+1 - x - 4) = (x+4)(5x-3)