Question

Descompuneți în factori , folosind metoda factorului comun : va rog ​

Answer 1

Răspuns:

Explicație pas cu pas:

b)=3x(3x-1)

d)=2x²(7x+1)

f)=8x³(3x²+2)

b) 4x³(3x²+2x-1)=4x³[(x²-1)+(2x²+x)]=4x³(x+1)(x-1+2x)=4x³(x+1)(3x-1)

d) 7x^4(4x^4-3x²+2)

4t²-3t+2=0       t1,2=3±√9-32/8    nu are solutii reale    

f)8x^4(3x^5-6x^4+4)

 

b)(x+3)(x-2-2)=(x+3)(x-4)

d) (x+7)(x+5+6)=(x+7)(x+11)

b) (x-1)(3x+2+1-2x)=(x-1)(x+3)

d)(5x-3)(4x+1-6x-3)=(5x-3)(-2x-2)=(3-5x)(x+1)

b) (x-2)(x-2+3-5x)=(x-2)(1-4x)

d) (x+4) (6x+1-x-4)=(x+4)(5x-3)