Question

Descompuneti in factori, grupand mai intai convenabil termenii: a) 2x+2y+ax+ay b) 5x-5y+ax+-ay c)xy+xz+5y+5z d)3x+3y+a^2x+a^2y

Answer 1

Răspuns:

Explicație pas cu pas:

2x+2y+ax+ay =2(x+y)+a(x+y)=(x+y) (2+a)

5x-5y+ax+-ay =5(x-y)+a(x-y)=(x-y)(5+a)

xy+xz+5y+5z=x(y+z)+5(y+z)=(y+z) (x+5)

3x+3y+a²x+a²y=3(x+y) +a²(x+y)=(3+a²)(x+y)