Question

Descompuneti in factori primi si aflati nr. de divizori ai nr.32;27;170;450;1350;252;350;1800

Answer 1

32=2^5       ^-putere
nr.de divizori:d(n)=(a1+1)(a2+2)....(an+1)
d(32)=(5+1)=6
27=3³
d(27)=(3+1)=4
170=17·2·5
d(170)=(1+1)(1+1)(1+1)=2×2×2=8
450=2·5²·3²
d(450)=(1+1)(2+1)(2+1)=2·3·3=18
1350=2·5²·3³
d(1350)=(1+1)(2+1)(3+1)=2·3·4=24
252=2²·3²·7
d(252)=(2+1)(2+1)(1+1)=3·3·2=18
350=2·5²·7
d(350)=(1+1)(2+1)(1+1)=2·3·2=12
1800=2³·3²·5²
d(1800)=(3+1)(2+1)(2+1)=4·3·3=36