Question

Descompuneti in factori primi (x la patrat +4x+2)*(x la patrat +4x+6)+4

Answer 1

[tex] (x^{2} +4x+2)( x^{2} +4x+6)+4= =(x^{2} +2x+1+2x+1)( x^{2} +4x+4+2x)+4= =[(x+1)^{2}+(2x+1)][(x+2)^{2}+(2x+4)]+4= (x+1)^{2}(x+2)^{2}+(x+1)^{2}(2x+4)+(x+2)^{2}(2x+1)+ +(2x+4)(2x+1)+4= =(x+1)^{2}(x+2)^{2}+(x+1)^{2}[(2x+1)+3]+(x+2)^{2}(2x+1)+ +[(2x+1)+3](2x+1)+4= =(x+1)^{2}(x+2)^{2}+(x+1)^{2}(2x+1)+3(x+1)^{2}+(x+2)^{2}(2x+1)+ +(2x+1)^{2}+3(2x+1)+4 Cam atat am reusit sa rezolv :D[/tex]