Question

descompuneti in factori
$( \sqrt{2} x - 1) ^{2} - 32 {x}^{2}$
​

Answer 1

Răspuns:

Explicație pas cu pas:

(√2 x  - 1)²  - 32x² =

(√2 x  - 1)² - (4√2 x )² =

(x√2 - 1 - 4x√2)(x√2 - 1 + 4x√2) =

( - 1 - 3x√2) (5x√2 - 1 )

Answer 2

$\it (\sqrt2x-1)^2-32x^2= (\sqrt2x-1)^2-(4\sqrt2x)^2=\\ \\ =(\sqrt2x-1-4\sqrt2x)(\sqrt2x-1+4\sqrt2x)=(-3\sqrt2x-1)(5\sqrt2x-1)=\\ \\ =(1+3\sqrt2x)(1-5\sqrt2x)$