Question

Descompuneti in products de factori:
a) (x-2)^2-(2x+1)^2
b) x^2+ 10x+25
c) x^2+8x+12​

Answer 1

Răspuns:

a)(x^2-2x2+4)-(4x^2+4x+1)=x^2-4x+4-4x^2+4x+1=3x^2+5

b)x^2+10x+25

a=1 b=10 c=25

delta=b^2-4ac=100-100=0=> x nu are soluții

c)x^2+8z+12

a=1 b=8 c=12

delta=b^2-4ac=64-48=16=>

x1=-b + radical din delta : 2a=-8+8:1=0

x2=-b- radical din delta:2a=16:2=8=>

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