Question

Descompuneți nr 1000 în nr direct proporționale cu 3,6,11
Cât de repede puteți pls​

Answer 1

 

$\displaystyle\bf\\x;~y;~z~~d.p.~~3;~6;~11\\\\Metoda~1~de~rezolvare:\\\\k=\frac{1000}{3+6+11}=\frac{1000}{20}=50\\\\x=3\times50=150\\y=6\times50=300\\z=11\times50=550\\\\\\Metoda~2~de~rezolvare:\\\\\frac{x}{3}=\frac{y}{6}=\frac{z}{11}=k\\\\x=3k\\y=6k\\z=11k\\\\x+y+z=1000\\3k+6k+11k=1000\\20k=1000\\\\k=\frac{1000}{20}=50\\\\x=3k=3\times50=150\\y=6k=6\times50=300\\z=11k=11\times50=550$

 

 

 

Answer 2

Notare nr. : a, b, c

(a, b, c) d. p ( 3,6,11)

a/3 = b/6=c/11 = k

a=3k, b=6k, c=11 k

a+b+c= 1000 => 3k+6k+11k = 1000

20 k = 1000 => k=1000 : 20 = 50

a=3 * 50 =>a=150

b=6 * 50 =>b=300

c=11 * 50 =>c=550

Verificare : 150 + 300 + 550 = 450 + 550 = 1000 ☑️

Numerele sunt : 150,300,550