Question

descompuneti nr 198 in parti invers proportionale cu 1/2 , 1/3 si1/6

Answer 1

i.p. cu 1/2, 1/3 si 1/6⇔d.p cu 2,3 si 6


x/2=y/3=c/6=(x+y+z)/(2+3+6)=198/11=18
x=2*18=36
y=3*18=54
z=6*18=108