Question

Descompuneti și calculati va rog frumos urgent va rog

Answer 1

$1( \frac{4}{3 \sqrt{3} } + \frac{2}{ \sqrt{3} } + \frac{8 \sqrt{3} }{9} ) \times ( - \frac{7 \sqrt{3} }{9} ) =$

$( \frac{10}{3 \sqrt{3} } + \frac{8 \sqrt{3} }{9} ) \times ( - \frac{7 \sqrt{3} }{9} ) =$

$( \frac{10 \sqrt{3} }{9} + \frac{8 \sqrt{3} }{9} ) \times (- \frac{7 \sqrt{3} }{9} ) =$

$2 \sqrt{3} \times( - \frac{7 \sqrt{3} }{9} ) =$

$- 2 \sqrt{3} \times \frac{7 \sqrt{3} }{9} =$

$- \frac{42}{9} = - \frac{14}{3}$

$2( \frac{3}{ \sqrt{8} } - \frac{5}{ \sqrt{18} } + \frac{ \sqrt{2} }{6} ) \times 2 \sqrt{2} =$

$2( \frac{3}{2 \sqrt{2} } - \frac{5}{3 \sqrt{2} } + \frac{ \sqrt{2} }{6} ) \times 2 \sqrt{2} =$

$2( - \frac{1}{6 \sqrt{2} } + \frac{ \sqrt{2} }{6} ) \times 2 \sqrt{2} =$

$2( - \frac{ \sqrt{2} }{12} + \frac{ \sqrt{2} }{6} ) \times 2 \sqrt{2} =$

$2 \times \frac{ \sqrt{2} }{12} \times 2 \sqrt{2} =$

$\frac{ \sqrt{2} }{6} \times 2 \sqrt{2} =$

$\frac{ \sqrt{2} }{3} \times \sqrt{2} =$

$\frac{2}{3}$