Question

descompuneți următoarele nr naturale in baza 10 :812,1121,67008,12014, a7b,a19b

Answer 1

812=8x100+10x1+2

1121= 1.000x1+100x1+10x2+1

67.008=10.000x6+1.000x7+0x100+0x10+8

12.014=10.000x1+1.000x2+100x0+10x1+4

a7b= 100xa+10x7+b

a.19b= 1000xa+100x1+10x9+b

Answer 2

812 = 8 × 100 + 1 × 10 + 2
1.121 = 1 × 1.000 + 1 × 100 + 2 × 10 + 1
67.008 = 6 × 10.000 + 7 × 1.000 + 8
12.014 = 1 × 10.000 + 2 × 1.000 + 1 × 10 + 4
a 7b = a×100 + 7 × 10 + b
a19b = a × 1000 + 1 × 100 + 9 × 10 + b