Question

Descomuneti in factori
a) 1/ 36 x^2 - y^4
b) 5x^2+30x +45
c) X^3 + 3x^2 - 4x -12

Answer 1

Răspuns:

a) (1/6x - y^2)(1/6x+y^2)

b) 5(x^2+6x+9) = 5(x+3)^2

c) x^3 + 4x^2 + 4x - 12 -x^2 - 8x = x(x^2 + 4x +4) -(x^2+8x+12) =

x(x+2)^2 - (x^2 + 8x + 16 - 4) = x(x+2)^2 - (x+4)^2 - 4  

Explicație pas cu pas:

Answer 2

Răspuns:

(1/6)^2×2²-(y²)²=

(1/6×)^2-(y²)²=

(1/6x-y²)(1/6x+y²)

b) 5x(x+6x+7)

5x(7x+7)

c)x^2(×+3)-4(x+3)

(x+3)(x^2-4)

(x+3)(x-2)(x+2)