Question

descopuneți in factori primi:

(3-4x)²-(x-3)²

(11x-6)²-(3x-1)²

(7-2x)²-(x+2)²

(3x-5)²-(2x-3) ²

4(6-5x)²-(x²-x+3)²
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Answer 1

Răspuns:

Explicație pas cu pas:

(3-4x)²-(x-3)² = (3-4x-x+3)(3-4x+x-3) = (6-5x)(-3x) = 3x(5x-6)

(11x-6)²-(3x-1)² = (11x-6-3x+1)(11x-6+3x-1) = (8x-5)(14x-7) = 7(8x-5)(2x-1)

(7-2x)²-(x+2)² = (7-2x-x-2)(7-2x+x+2) = (5-3x)(9-x) = (x-9)(3x-5)

(3x-5)²-(2x-3)² = (3x-5-2x+3)(3x-5+2x-3) = (x-2)(5x-8)

4(6-5x)²-(x²-x+3)² = [2(6-5x)]² - (x²-x+3)² = (12-10x)² - (x²-x+3)² =

= (12-10x-x²+x-3)(12-10x+x²-x+3) = (-x²-9x+9)(x²-11x+15)

Am folost formula :

a²-b² = (a-b)(a+b)

Answer 2

Răspuns:

(3-4X+X-3)(3-4X-X+3)=-3X(6-5X)        (11X-6+3X-1)(11X-6-3X+1)=7(2X-1)(8X-5) ;                            (7-2X+X+2)(7-2X-X-2)=(9-X)(5-3X) ;    ((3X-5+2X-3)(3X-5-2X+3)=(5X-8)(X-2)

Explicație pas cu pas: