Question

desfaceti parantezele drepte.....
paranteza 3a(x plus 1) la puterea a 2 supra b(x minus 1)inchidem paranteza p dreaptasi tpotul la puterea a 3

Answer 1

$[3a ( x+1)^{2}/ b(x-1) ] ^{3} = \frac{27a^{3}( x+1) ^{6} }{b ^{3}(x-1) ^{3} }$