Question

desopera numarul n care indeplineste conditia n×n=n+n.Cate solutî exista

Answer 1

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Answer 2

n²=2n ⇔n²-2n+1=1 ⇔(n-1)²=1 ⇒n-1=1 ⇒n=2 sau n-1=-1 ⇒n=0;
Asadar S={0;2};