Question

det c.m.m.m.c-ul nr 9,12si 15​

Answer 1

Răspuns:

descompunem 9,12, 15 in factori primi

9 : 3

3 : 3

1

9 = 3 x 3

12 : 2

6 : 2

3 : 3

1

12 = 2 x 2 x 3

15 : 3

5 : 5

1

15 = 3 x 5

9 = 3 la a doua

12 = 2 la a doua x 3

15 = 3 x 5

[9;12;15] = 3 la a doua x 2 la a doua x 5 = 9 x 4 x 5 = 9 x 20 = 180

Answer 2

Răspuns:

12=2^2×3

9=3^2

15=3×5

Explicație pas cu pas:

c.m.m.m.c.=2^2×3^2×5=4×9×5=180

Succes!